The brakes applied to a car produce a negative acceleration of $a = 6 m s^{- 2}$ . If the car takes 2 seconds to stop after applying the brakes, calculate the distance it travels during this time. (Give your answer in m).

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Solution

The correct option is:A=12
Given Data:
$a = 6 m s^{- 2}$ , $t = 2 s$ and $v = 0 m/s$
Step 1: To find the distance;

Using first equation of motion;

$v = u + at,$ we get

$0 = u + (-6 \times 2)$ 0 = u + (–6 × 2)

$u = 12 m/s$

Now by using third equation of motion equation
$v^{2} = u^{2} - 2 a s$
$0^{2} = 12^{2} - 2 \times 6 \times s ⟹ s = \frac{144}{12} = 12 m$

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The brakes applied to a car produce a negative acceleration of a=6ms−2 . If the car takes 2 seconds to stop after applying the brakes, calculate the distance it travels during this time. (Give your answer in m).

The correct option is:A=12Given Data:a=6ms−2 , t = 2 s and v = 0 m/s Step 1: To find the distance; Using first equation of motion; v = u + at, we get 0 = u + (–6 × 2) 0 = u + (–6 × 2) u = 12 m/s Now by using third equation of motion equationv2=u2−2as 02=122−2×6×s⟹s=14412=12m

The brakes applied to a car produce a negative acceleration of $a = 6 m s^{- 2}$ . If the car takes 2 seconds to stop after applying the brakes, calculate the distance it travels during this time. (Give your answer in m).