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Question

The brakes applied to a car produce an acceleration of 6 ms-² in opposite direction to the motion. If the car takes 2 s to stop after the application of rakes, calculate the distance it travels during this time.

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Solution

Step 1: Given data

Acceleration(a) = -6 m/s2 (as brakes applied)

Time taken(t) = 2 sec

Final velocity(v) =0

Let 's' is the distance traveled and 'a' is acceleration.

Step 2: Formula used

v=u+at (First equation of motion)

s=ut+12at2 (Second equation of motion)

Step 3: Finding initial velocity

v=u+at

Putting all the values

0=u+(6)×2

Or, u = 12 m/s

Hence the initial velocity is 12 m/s.

Step 4: Finding the distance traveled

s=ut+12at2

Putting all the values

s=12×212×6×2×2

After solving

s = 12 m

Hence, the distance traveled = 12 m.


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