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Question

The capacitance of two capacitors are 2μF and 4μF. They are first connected in series combination and then in parallel combination .Find the ratio of equivalent capacitance in both the cases

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Solution

In series combination :
CS=C1×C2C1+C2=2μF×4μF6μF=8μF6=4μF3
In parallel combination :
CP=C1+C2=2μF+4μF=6μF
CSCP=4μF3×6μF=29

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