The capacitance of two capacitors are 2μF and 4μF. They are first connected in series combination and then in parallel combination .Find the ratio of equivalent capacitance in both the cases
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Solution
In series combination :
CS=C1×C2C1+C2=2μF×4μF6μF=8μF6=4μF3 In parallel combination : CP=C1+C2=2μF+4μF=6μF CSCP=4μF3×6μF=29