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Question

The capacitor in the circuit shown below is initially charged. After closing the switch, choose the correct option(s)


Correct Answer
A
Energy of the capacitor becomes half of its initial value in time. RC(ln 2)2
Correct Answer
B
Charge on the capacitor becomes half of its initial value in RC(ln2).
Correct Answer
C
Current in the circuit becomes half of its initial value in time RC(ln2).
Your Answer
D
Current in the circuit becomes half of its initial in time RCln 22

Solution

The correct options are
A Energy of the capacitor becomes half of its initial value in time. RC(ln 2)2
B Charge on the capacitor becomes half of its initial value in RC(ln2).
C Current in the circuit becomes half of its initial value in time RC(ln2).
q=q0etCR
For (A) part q02=q0etCR
Taking log on both sides
12loge2=tCR
t=RCloge2
(B) part q02=q0etCR
t=RCloge2
(C) part i02=i0etCR
t=RCloge2
(D) part t=RCloge2

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