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Question

The carbonyl compound producing an optically active product by reaction with LiAlH4 is:

A
propanone
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B
butanone
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C
3-pentanone
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D
benzophenone.
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Solution

The correct option is B butanone
CH3O||CCH3LiAIH4−−−−CH3OH|CHCH3

CH3O||CCH2CH3LiAlH4−−−CH3OH|C|HOpticallyactiveCH2CH3

H3CCH2O||CCH2CH3LiAlH4−−−H3CCH2OH|C|HCH2CH3

Option B is correct.

930864_938815_ans_2e9c7faeca454a1d978ed54c4a78355c.PNG

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