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Question
The carbonyl compound producing an optically active product by reaction with LiAlH4 is
The carbonyl compound producing an optically active product by reaction with LiAlH4 is
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Solution
The correct option is C butanone
Reactions:
A) H3C−CO−CH3LiAlH4−−−−→H3C−CH(OH)−CH3Optically Inactive
B) H3C−CH2−CO−CH3LiAlH4−−−−→H5C2−CH(OH)−CH3Optically Active
C) H3C−CH2−CO−CH2−CH3LiAlH4−−−−→H5C2−CH(OH)−C2H5Optically Inactive
D) C6−H5−CO−C6H5LiAlH4−−−−→C6H5−CH(OH)−C6H5Optically Inactive
Hence, Option "B" is the correct answer.
Reactions:
A) H3C−CO−CH3LiAlH4−−−−→H3C−CH(OH)−CH3Optically Inactive
B) H3C−CH2−CO−CH3LiAlH4−−−−→H5C2−CH(OH)−CH3Optically Active
C) H3C−CH2−CO−CH2−CH3LiAlH4−−−−→H5C2−CH(OH)−C2H5Optically Inactive
D) C6−H5−CO−C6H5LiAlH4−−−−→C6H5−CH(OH)−C6H5Optically Inactive
Hence, Option "B" is the correct answer.
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