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Question

The cell in which the following reaction occurs:

2Fe3+(aq)+2I(aq)2Fe2+(aq)+I2(s)

has Ecell=0.236 V at 298 K.

Calculate the standard Gibbs energy of the cell reaction. (Given : 1 F=96,500 C mol1)

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Solution

Standard Gibbs free energy of the cell is given by the formula:

ΔGo=nFEo=2×96500×0.236=45.54KJ

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