The charge on the cyclic silicate anion $[S i_{3} O_{9}]^{n -}$ is :

-2

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-3

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-4

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-6

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Solution

The correct option is D -6
General formula of cyclic silicates is $[S i O_{3}]_{k}^{2 k -}$ . Here k $=$ 3, n $=$ 2k-6.

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