The circuit shown here is in its steady state. Time constant of the circuit is

0.1 ms

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0.2 ms

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0.3 ms

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Solution

The correct option is B 0.2 ms
$\begin{matrix} l_{e q} = \frac{6 \times 3}{6 + 3} = 2 m H R_{e q} = (4 + 6) = 10 Ω ∴ τ = \frac{2}{10} = 0.2 m / s H e n c e, o p t i o n B i s c o r r e c t a n s w e r . \end{matrix}$

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The circuit shown here is in its steady state. Time constant of the circuit is

The correct option is B 0.2 msleq=6×36+3=2mHReq=(4+6)=10Ω∴τ=210=0.2m/sHence,optionBiscorrectanswer.

The correct option is B 0.2 ms
$\begin{matrix} l_{e q} = \frac{6 \times 3}{6 + 3} = 2 m H R_{e q} = (4 + 6) = 10 Ω ∴ τ = \frac{2}{10} = 0.2 m / s H e n c e, o p t i o n B i s c o r r e c t a n s w e r . \end{matrix}$