Question

The circumradius of the triangle whose sides are 13, 12 and 5 is

• A. 15
• B.
• C.
• D. 6

Answer 1

The correct option is B

Let sides are a = 13, b = 12, c =5

$Now,a^2=b^2+c^2\Rightarrow (13{)}^2=(12{)}^2+(5{)}^2\Rightarrow \angle A={90}^{0}Weknow,R=\frac{a}{2sinA}R=\frac{13}{2.sin{90}^0}=\frac{13}{2}$