The class marks of a distribution are 26, 31, 36, 41, 46, 51, 56, 61, 66, 71. Find the true class limits.

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Solution

Here,
Class size = Difference b/w any two consecutive class marks = 31-26 = 5
Therefore,
Lower limit of first class interval = $26 - \frac{5}{2} = 23.5$

Upper limit of first class interval = $26 + \frac{5}{2} = 28.5$

Therefore, first class interval is 23.5-28.5.
Thus, the class intervals are :
$23.5 - 28.5, 28.5 - 33.5, 33.5 - 38.5, 38.5 - 43.5, 43.5 - 48.5, 48.5 - 53.5$
Since, the classes are formed by exclusive method. Therefore, these limits are true class limits.

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