The common chord of the circle x2-y2-4 x-1-0 and x2-y2-6 x-2 y-3-0 isA- 5 x-y-2-0B- x-y-1-0C- 2 x-2 y-5-0D- 3 x-y-3-0

The correct option is B S_1=x^2+y^2+4x+1=0 S_2=x^2+y^2+6x+2y+3=0 Common chord ≡ S_1 S_2=0⇒ 2x+2y+2=0 ⇒ x+y+1=0 ...

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Standard XII

Mathematics

Length of Tangent and Power of a Point

The common ch...

Question

The common chord of the circle $x^{2} + y^{2} + 4 x + 1 = 0$ and $x^{2} + y^{2} + 6 x + 2 y + 3 = 0$ is

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Solution

The correct option is A

$S_{1} = x^{2} + y^{2} + 4 x + 1 = 0$

$S_{2} = x^{2} + y^{2} + 6 x + 2 y + 3 = 0$

Common chord $\equiv S_{1} - S_{2} = 0 \Rightarrow 2 x + 2 y + 2 = 0$

$\Rightarrow x + y + 1 = 0$

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The common chord of the circle x2+y2+4x+1=0 and x2+y2+6x+2y+3=0 is

The correct option is A S1=x2+y2+4x+1=0 S2=x2+y2+6x+2y+3=0 Common chord ≡S1−S2=0⇒2x+2y+2=0 ⇒x+y+1=0

The common chord of the circle $x^{2} + y^{2} + 4 x + 1 = 0$ and $x^{2} + y^{2} + 6 x + 2 y + 3 = 0$ is

The correct option is A

$S_{1} = x^{2} + y^{2} + 4 x + 1 = 0$

$S_{2} = x^{2} + y^{2} + 6 x + 2 y + 3 = 0$

Common chord $\equiv S_{1} - S_{2} = 0 \Rightarrow 2 x + 2 y + 2 = 0$

$\Rightarrow x + y + 1 = 0$