The complete solution set of the in equation $(x + 4) (x - 1) (x - 3) (x + 1) < 0$ is $x \in (a, b) \cup (c, d)$ , then?

a + b + c + d = - 1

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a + b + c + d = 2

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a b c d = 12

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a b + c d = 7

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Solution

The correct options are
A $a + b + c + d = - 1$
C $a b c d = 12$

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