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Question

The complex number z (Re(z)2) satisfies the equation z2=4z+|z|216|z|3, then the value of |z|4 is

A
1
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B
4
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C
16
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D
256
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Solution

The correct option is B 4
Let z=x+iy
x2y2+2ixy=4x+4iy+a, where a is a real number
2xy=4y (equating the imaginary part)y=0 (x2)z=x

x2=4x+x216x34x16x3=0x4=4|z|4=4

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