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Structural Isomerism

The complex, ...

Question

The complex, $[P t (P y) (N H_{3}) B r C l]$ will have how many geometrical isomers?

A

3

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B

4

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C

0

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D

2

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Solution

The correct option is A 3
$[P t (P y) (N H_{3}) B r C l]$ is $M A B C D$ type compound. It will have 3 geometrical isomers.

Hence option A is correct.

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Similar questions

Q. The complex,

[P t (P y) (N H_{3}) B r C l]

will have how many geometrical isomers?

The complex $[P t (P y) (N H_{3}) B r C l]$ will have how many geometrical isomers?

Q. The complex,

[P t (P y) (N H_{3}) B r C l]

will have how many geometerical isomers?

Q. How many geometrical isomers are possible with the complex,

[P t (p y) (N H_{3}) B r C l]

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[N I (C l)_{2} (P (C H_{3})_{3})_{2}]

is a paramagnetic complex of Ni(II), Analgous Pd(II) complex is diamagnetic. How many geometrical isomers will be possible for Ni(II) and Pd(II) complexes? Also explain their magnetic behaviour.

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