The composition of a sample of wustite is $F e_{0.93} O_{1.00}$ . What percentage of iron is present in the form of Fe III?

15%

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24%

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12%

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11%

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Solution

The correct option is A 15%
Oxidation no. of Fe in wustite is 200/93 = 2.15. It is an intermediate value between two oxidation state of Fe as, Fe (II) and (III)
Let percentage of Fe(III) be $α$ , then
2 x ( 100 - $α$ ) + 3 x $α$ = 2.15 x 100
$α = 15$
or
$∴$ Percentage of Fe(III) = 15%

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