Question

The compound which does not disproportionate on hydrolysis is:

• A. $Xe{F}_6$
• B. $Xe{F}_4$
• C. $C{l}_2$
• D. $B{r}_2$

Answer 1

The correct option is A $Xe{F}_6$

$a)Xe{F}_6+3H_{2}O\to Xe{O}_3+6HF$
Here, the oxidation state of all elements remain the same in both the reactants and the products so it is not a redox reaction.
$b)4\stackrel{+4}{Xe}{F}_4+12H_{2}O\to 2\stackrel{+6}{Xe}{O}_3+4\stackrel{0}{Xe}+24HF+3O_2$
Here, $Xe$ is getting oxidised as well as reduced. This is a disproportionation reaction.
$c)\stackrel{0}{C}{l}_2+H_{2}O\to HO\stackrel{+1}{C}l+H\stackrel{-1}{C}l$
This is a disproportionation reaction.
$d)\stackrel{0}{B}{r}_2+H_{2}O\to HO\stackrel{+1}{B}r+H\stackrel{-1}{B}r$
This is a disproportionation reaction.