The compound which forms a dative bond with ammonia is

C C l_{4}

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B C l_{3}

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M g C l_{2}

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N a C l

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Solution

The correct option is D $B C l_{3}$
The compound which forms a dative bond with ammonia is $B C l_{3}$ due to presence of a vacant orbital in Boron of $B C l_{3}$ .
Hence, Option "B" is the correct answer.

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Similar questions

Q. Consider the compounds

B C l_{3}

and

C C l_{4}

. How will they behave with water? Justify.

Consider the compounds, $B C l_{3}$ and $C C l_{4}$ . How will they behave with water? Justify.

Q. (a) Explain why, ionic compounds conduct electricity in solution whereas covalent compounds do not conduct electricity.
(b) Which of the following will conduct electricity and which not?
MgCl₂, CCl₄, NaCl, CS₂, Na₂S
Give reasons for your choice.

(a) Explain why ionic compounds conduct electricity in solution whereas covalent compounds do not conduct electricity.
(b) Which of the following will conduct electricity and which not?
$M g C l_{2}, C C l_{4}, N a C l, C S_{2}, N a_{2} S$
Give reasons for your choice.

Q. Among

L i C l, B e C l_{2}, B C l_{3}

and

C C l_{4}

the covalent bond character follows the order

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The compound which forms a dative bond with ammonia is

The correct option is D BCl3The compound which forms a dative bond with ammonia is BCl3 due to presence of a vacant orbital in Boron of BCl3.Hence, Option "B" is the correct answer.

The correct option is D $B C l_{3}$
The compound which forms a dative bond with ammonia is $B C l_{3}$ due to presence of a vacant orbital in Boron of $B C l_{3}$ .
Hence, Option "B" is the correct answer.