Question

# The compound which reacts with $$'HBr'$$ obeying markovnikov's rule is :

A
H2C=CH2
B
H3CCH=CHCH3
C
CH3CH2CH=CHCH3
D
(CH3)CH=CH2

Solution

## The correct options are C $${ CH }_{ 3 }{ CH }_{ 2 }CH=CH-{ CH }_{ 3 }$$ D $$\left( { CH }_{ 3 } \right) CH={ CH }_{ 2 }$$As option A & B are symmetrical so it will make same product and there is no use of markovnikov's rule.But in case of C & D,Alkenes are unsymmetrical so it will make different product when it reacts with HBr in presence of peroxide according to anti-markovnikov's rule.Chemistry

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