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Question

The compound which reacts with $$'HBr'$$ obeying markovnikov's rule is :


A
H2C=CH2
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B
H3CCH=CHCH3
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C
CH3CH2CH=CHCH3
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D
(CH3)CH=CH2
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Solution

The correct options are
C $${ CH }_{ 3 }{ CH }_{ 2 }CH=CH-{ CH }_{ 3 }$$
D $$\left( { CH }_{ 3 } \right) CH={ CH }_{ 2 }$$
As option A & B are symmetrical so it will make same product and there is no use of markovnikov's rule.
But in case of C & D,
Alkenes are unsymmetrical so it will make different product when it reacts with HBr in presence of peroxide according to anti-
markovnikov's rule.

Chemistry

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