Question

# The concentration of fluoride, lead, nitrate and iron in a water sample from an underground lake was found to be $$1000\ ppb, 40\ ppb, 100\ ppm$$ and $$0.2\ ppm$$, respectively. This water is unsuitable for drinking due to high concentration of :

A
B
nitrate
C
iron
D
fluoride

Solution

## The correct option is A nitrateFluoride $$\displaystyle = 1000 ppb = \dfrac {1000}{1000}= 1 ppm$$Lead $$\displaystyle = 40 ppb = \dfrac {40}{1000} ppm = 0.04 ppm$$We can see that the concentration of nitrate is maximum (100 ppm). Note: > 40 ppm gives blue baby syndrome disease.Hence, this water is unsuitable for drinking due to the high concentration of nitrate.Chemistry

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