The concentration of fluoride, lead, nitrate and iron in a water sample from an underground lake was found to be $1000 p p b, 40 p p b, 100 p p m$ and $0.2 p p m$ , respectively. This water is unsuitable for drinking due to high concentration of :

lead

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nitrate

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iron

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fluoride

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Solution

The correct option is A nitrate
Fluoride $= 1000 p p b = \frac{1000}{1000} = 1 p p m$

Lead $= 40 p p b = \frac{40}{1000} p p m = 0.04 p p m$

We can see that the concentration of nitrate is maximum (100 ppm). Note: > 40 ppm gives blue baby syndrome disease.

Hence, this water is unsuitable for drinking due to the high concentration of nitrate.

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The concentration of fluoride, lead, nitrate and iron in a water sample from an underground lake was found to be 1000 ppb,40 ppb,100 ppm and 0.2 ppm, respectively. This water is unsuitable for drinking due to high concentration of :

The correct option is A nitrateFluoride =1000ppb=10001000=1ppmLead =40ppb=401000ppm=0.04ppmWe can see that the concentration of nitrate is maximum (100 ppm). Note: > 40 ppm gives blue baby syndrome disease.Hence, this water is unsuitable for drinking due to the high concentration of nitrate.

The concentration of fluoride, lead, nitrate and iron in a water sample from an underground lake was found to be $1000 p p b, 40 p p b, 100 p p m$ and $0.2 p p m$ , respectively. This water is unsuitable for drinking due to high concentration of :