Question

The contents of urn I and II are as follows:
Urn I: 4 white and 5 black balls
Urn II: 3 white and 6 black balls
One urn is chosen at random and a ball is drawn and its colour is noted and replaced back to the urn. Again a ball is drawn from the same urn colour is noted and replaced. The process is repeated 4 times and as a result one ball of white colour and 3 of black colour are noted. Find the probability the chosen urn was I.

• A. $\frac{125}{287}$
• B. $\frac{64}{127}$
• C. $\frac{25}{287}$
• D. $\frac{79}{192}$

Answer 1

The correct option is A $\frac{125}{287}$