The conversion (Image) Can be effected using

B r_{2} / C C l_{4}

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B r_{2} / H_{2} O

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B r_{2} / F e

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B r_{2} / b e n z o y l p e r o x i d e

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Solution

The correct option is C $B r_{2} / F e$

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Similar questions

(C H_{3} - C H_{3} \to C H_{3} - C H_{2} - O H) alkane \to alcohol

C_{6} H_{5} - C O O A g + B r_{2} + C C l_{4} + r e f l u x \to

B r_{2} / C C l_{4}

3 B r_{2} + 6 C O_{3}^{2 -} + 3 H_{2} O \to 5 B r^{⊖} + B r O_{3}^{⊖} + 6 H C O_{3}^{⊖}

H_{2} + B r_{2} \to 2 H B r

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