The conversion of A to B follows second order kinetics. Doubling the concentration of A increases the rate of formation of B by a factor of
The correct option is B 4 For a second order kinetics of the reaction A → B we have rate = k[A]2. When conc. of A is doubled the rate of the reaction increases by a factor of 22(=4). Since rate of conversion of A = rate of formation of B. Hence rate of formation of B also increases 4 times.