The correct decreasing order of basic strength of the following species is:

O H^{-} > N H_{2}^{-} > H_{2} O > N H_{3}

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N H_{2}^{-} > O H^{-} > N H_{3} > H_{2} O

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N H_{3} > H_{2} O > N H_{2}^{-} > O H^{-}

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H_{2} O > N H_{3} > O H^{-} > N H_{2}^{-}

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Solution

The correct option is B $N H_{2}^{-} > O H^{-} > N H_{3} > H_{2} O$
The correct decreasing order of basic strength of the following species is $N H_{2}^{-} > O H^{-} > N H_{3} > H_{2} O$ .
Ammonia is basic whereas water is neutral. Thus $N H_{3} > H_{2} O$

Since water is more acidic than ammonia, its conjugate base $O H^{-}$ ion is weaker base than $N H_{2}^{-}$ ion. Hence, $N H_{2}^{-} > O H^{-}$

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