The correct decreasing order of $p K_{a}$ in the given compound is:

I I > I V > I > I I I

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I V > I I > I I I > I

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I I I > I I > I V > I

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I V > I > I I > I I I

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Solution

The correct option is A $I I > I V > I > I I I$
Weaker acids have higher $p K_{a^{-}} - O C H_{3}$ at meta-position exerts only $- I$ effect, hence increases the acidity.

$- I$ effect order: $- N O_{2} > - O C H_{3} > - C l$
$- C H_{3}$ has $+ I$ effect.

$p K a$ is inversely proportional to acidity.

So, option A is correct.

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Similar questions

Q. The correct decreasing order of -I effect of the given groups will be:

(i) C N (i i) N O_{2} (i i i) N H_{2} (i v) F

Q. The decreasing order of

- I

effect for the given groups is:
(i)

- C N

(ii)

- N O_{2}

(iii)

- N H_{2}

(iv)

- F

Mark the correct order of decreasing acid strength of the following compounds.

(a) V > IV > II > I > III
(b) II > IV > I > III > V
(c) IV > V > III > II > I
(d) V > IV > III > II > I

Q. Arrange the following compounds in decreasing order of their reactivity with sodium methoxide in methanol at

50^{\circ}

Order of decreasing acidity of

$(i) H C O O H (i i) C H_{3} C O O H (i i i) C l_{2} C H C O O H (i v) C F_{3} C O O H i s$

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The correct decreasing order of pKa in the given compound is:

The correct option is A II>IV>I>IIIWeaker acids have higher pKa−−OCH3 at meta-position exerts only −I effect, hence increases the acidity.−I effect order: −NO2>−OCH3>−Cl−CH3 has +I effect.pKa is inversely proportional to acidity.So, option A is correct.

The correct decreasing order of $p K_{a}$ in the given compound is: