The correct order of acid strength of oxyacids is:

H C l O > H C l O_{2} > H C l O_{3} > H C l O_{4}

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H C l O_{2} > H C l O_{3} > H C l O > H C l O_{4}

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H C l O_{4} > H C l O_{3} > H C l O_{2} > H C l O

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H C l O_{3} > H C l O_{4} > H C l O > H C l O_{2}

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Solution

The correct option is D $H C l O_{4} > H C l O_{3} > H C l O_{2} > H C l O$
The acid strength of oxyacids of the same halogen increases with increase in oxidation state of the halogen $+ 7 H C l O_{4} > + 5 H C l O_{3} > + 3 H C l O_{2} > + 1 H C l O$ .
Thus $C l$ in $H C l O_{4}$ is in highest oxidation state $(+ 7)$ and hence strongest acid, while $H C l O (C l$ is in $+ 1$ oxidation state $)$ is weakest.

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Similar questions

Arrange the following compounds according to the increasing order of oxidation state of chlorine.

$H C l O_{4}, H C l O_{3}, H C l O_{2}, H C l O$

H C l O < H C l O_{2} < H C l O_{3} < H C l O_{4}

H C l O < H C l O_{2} < H C l O_{3} < H C l O_{4}

H C l O_{4}, H C l O_{3}, H C l O_{2}, H C l O

H C l O, H C l O_{2}, H C l O_{3}, H C l O_{4}

H C l O_{4} < H C l O_{3} < H C l O_{2} < H C l O

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