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Question

The correct order of equivalent conductances at infinite dilution of LiCl,NaCl and KCl is:

A
LiCl>NaCl>KCl
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B
KCl>NaCl>LiCl
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C
NaCl>KCl>LiCl
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D
LiCl>KCl>NaCl
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Solution

The correct option is B KCl>NaCl>LiCl
Since the anions are same so we will compare the size of cations.
Li+ < Na+ < K+.

But due to hydration of cation, the order of radii becomes
Li+ >Na+ >K+
We know that,
Conductance α 1radii

The order becomes KCl > NaCl > LiCl

Hence the correct option is 'C'.

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