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Question

The correct order of ionic radii is :

A
Te2 > I > Cl > Ar+
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B
I > Te2 > Cl > Ar+
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C
I > Te2 > Ar+ > Cl
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D
I > Cl >Te2 > Ar+
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Solution

The correct option is A Te2 > I > Cl > Ar+
Size ∝ number of shells.
Number of shells present in Te2 & I (five shells) are more than that in Cl & Ar+ (three shells).
Te2 & I are isoelectronic.
Since, size ∝ negative charge.
So, Te2 > I and Cl > Ar+.
Combining both factors, overall order is:
Te2 > I > Cl > Ar+


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