The correct order of radii is :

N a < L i < K

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F e^{3 +} < F e^{2 +} < F e^{4 +}

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F^{-} < O^{2 -} < N^{3 -}

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N < B e < B

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Solution

The correct option is C $F^{-} < O^{2 -} < N^{3 -}$
Effective nuclear charge i.e. $(\frac{z}{e})$ ratio decreases from $F^{-}$ to $N^{3 -}$
${(\frac{z}{e})}_{F^{-}} = \frac{9}{10} = 0.9$
${(\frac{z}{e})}_{O^{2 -}} = \frac{8}{10} = 0.8$
${(\frac{z}{e})}_{N^{3 -}} = \frac{7}{10} = 0.7$
Effective nuclear charge is inversely proportional to anionic radii. Hence the radii follows the order :
$F^{-} < O^{2 -} < N^{3 -}$

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Similar questions

The correct order of ionic radii of the species $N^{3 -}, O^{2 -}, N a^{+}$ and $F^{-}$ is:

F e

F e^{2 +}

F e^{3 +}

A l^{3 +} < M g^{2 +} < N a^{+} < F^{-}

T e^{2 -} > I^{-} > C s^{+} > B a^{2 +}

F e^{3 +} < F e^{2 +} < F e^{4 +}

M g > A l > S i > P

N a, L i, R b,

K

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