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Question

The correct order of reactivity of PhMgBr with following compounds will be:
(1).(C6H5)2CO, (2).CH3CH=O, (3).(CH3)2C=O

A
1>2>3
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B
2>3>1
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C
3>2>1
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D
1>3>2
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Solution

The correct option is B 2>3>1
As the positive charge decreases and steric hinderance increases on carbonyl group, the rate of nucleophilic addition reaction decreases.

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