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Electronic Configuration and Oxidation States

The correct o...

Question

The correct order of the oxidation states of nitrogen in $N O, N_{2} O, {N O}_{2}$ and $N_{2} O_{3}$ is:

{N O}_{2} < N_{2} O_{3} < N O < N_{2} O

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{N O}_{2} < N O < N_{2} O_{3} < N_{2} O

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N_{2} O < N_{2} O_{3} < N O < {N O}_{2}

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N_{2} O < N O < N_{2} O_{3} < {N O}_{2}

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Solution

The correct option is C $N_{2} O < N O < N_{2} O_{3} < {N O}_{2}$
The correct order of oxidation state of nitrogen in oxides of nitrogen is as follows:

$N_{2} O < N O < N_{2} O_{3} < N O_{2}$
$+ 1 < + 2 < + 3 < + 4$

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