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Question

The correct relation between hydrolysis constant (Ka) and degree of hydrolysis (h) for the following equilibrium is: 
CH3COO+H2OhydrolysisCH3COOH+OH 


A
h=KwCKa
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B
h=KwKaC
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C
h=KaCKw
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D
h=KaKwC
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Solution

The correct option is B h=KwKaC
Salt of weak acid and strong base. If C is the concentration and  h is the degree of hydrolysis, then at equilibrium :
CH3COOC(1h)+H2OhydrolysisCH3COOHCh+OHCh 

Kh=[CH3COOH][OH][CH3COO]=Ch×ChC(1h)=Ch21h
CH3COOHCH3COO+H+Ka=[CH3COO][H+][CH3COOH]H2OH++OHKw=[H+][OH]
We see that 
Kh=KwKa=Ch21hh<<<1Then, 1h1KwKa=Ch2h=KwKaC

Chemistry

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