Question

The correct shape and hybridization for $Xe{F}_4$ are:

• A. Planar triangle, $s{p}^3{d}^3$
• B. square planar, $s{p}^3{d}^2$
• C. octahedral, $s{p}^3{d}^2$
• D. trigonal bipyramidal, $s{p}^{3}d$

Answer 1

Answer: (B)

square planar, $s{p}^3{d}^2$

$Xe{F}_4,A{B}_4{L}_2\to s{p}^3{d}^2$
$\to$ geometry $\to$ octahedral
$\to$ shape $\to$ square planar