The cost of cultivating a field in the shape of a parallelogram at $50$ Paise per $m^{2}$ is Rs. $640$ . If the height of the parallelogram is $32$ m, find the base of the field.

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Solution

Area of the field =Rs. $640 \div R e \frac{1}{2}$
$= 1280 m^{2}$
$∴ B a s e \times 32 = 1280$
$B a s e = 1280 \div 32 = 40 m$

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The cost of cultivating a field in the shape of a parallelogram at 50 Paise per m2 is Rs. 640. If the height of the parallelogram is 32 m, find the base of the field.

Area of the field =Rs.640÷Re12=1280m2∴Base×32=1280Base=1280÷32=40m

The cost of cultivating a field in the shape of a parallelogram at $50$ Paise per $m^{2}$ is Rs. $640$ . If the height of the parallelogram is $32$ m, find the base of the field.

Area of the field =Rs. $640 \div R e \frac{1}{2}$
$= 1280 m^{2}$
$∴ B a s e \times 32 = 1280$
$B a s e = 1280 \div 32 = 40 m$