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Question

The current flowing when a potential difference of 33 V is applied across an appliance having a resistance of 110 Ω is I. If the same current (I) is to flow through an appliance having a resistance of 500 Ω, how much potential difference should be applied across it?
  1. 220 V
  2. 110 V
  3. 250 V
  4. 150 V


Solution

The correct option is D 150 V
Given :
First case-
Potential difference applied, V1=33 V
Resistance connected, R1=110 Ω
Second case-
Resistance connected, R2=500 Ω
Current in both cases is I

According to Ohm's Law,
V=IR
V1V2=I1R1I2R2
V2=V1R2R1I1=I2=I
V2=33×500110=150 V
The required potential difference between its two ends:
V2=150 V

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