Question

# The current in a coil of $$L=40 mH$$ is to be increased uniformly from $$1A$$ to $$11A$$ in $$4$$ milliseconds. The induced e.m.f. will be

A
100V
B
0.4V
C
440V
D
40V

Solution

## The correct option is A $$100 V$$$$e=\dfrac {LdI}{dt}$$$$=\dfrac {40\times 10^{-3}(11-1)}{4\times 10^{-3}}$$$$=100V$$Physics

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