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Question

The current in a coil of $$L=40 mH$$ is to be increased uniformly from $$1A$$ to $$11A$$ in $$4$$ milliseconds. The induced e.m.f. will be


A
100V
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B
0.4V
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C
440V
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D
40V
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Solution

The correct option is A $$100 V$$
$$e=\dfrac {LdI}{dt}$$
$$=\dfrac {40\times 10^{-3}(11-1)}{4\times 10^{-3}}$$
$$=100V$$

Physics

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