Question

The current through the 10 $\Omega$ resistor shown in figure is

• A. 0.1 A
• B. 0.2 A
• C. 0.3 A
• D. zero

Answer 1

The correct option is D zero

applying kvl

first in loop ABCDE

$-3i-6(i-i_1$) + 4.5=0 . -------(1)

then in loop ABCMNE

$-3i-10i_1-3+4.5=0$ . --------(2)

From equation (1) and (2) WE GET,

$i_1=0$

hence current passing through 10 ohm resistor is ZERO