The current-voltage graph for a given metallic wire at two different temperatures $T_{1}$ and $T_{2}$ is shown in the figure. The temperature $T_{1}$ and $T_{2}$ are related as:

T_{1} > T_{2}

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T_{1} < T_{2}

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T_{1} = T_{2}

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T_{1} > 2 T_{2}

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Solution

The correct option is B $T_{1} < T_{2}$
Ohm’s law V = IR
$R = \frac{V}{I} = s l o p e o f V - I g r a p h$
Slope for A < B
$R_{A} < R_{B}$
Resistance $\propto$ temperature
$∴$ resistance increases with increase in temperature
$T_{B} > T_{A}$
$T_{2} > T_{1}$

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