The daily minimum temperature recorded in degree F at a place during a week was as under-2-c- Monday Tuesday Wednesday Thursday Friday Saturday 35-5 30-8 27-3 32-1 23-8 29-9 Find the mean temperature-

Daily minimum temperatures = 35.5, 30.8, nbsp;27.3, 32.1, 23.8 and 29.9 Thus, we have: Mean #160;temperature=35.5 #160;+ #160;30.8+27.3+32.1+23.8+29.96 ...

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Standard IX

Mathematics

Range of Data

The daily min...

Question

The daily minimum temperature recorded (in degree F) at a place during a week was as under:

Monday Tuesday Wednesday Thursday Friday Saturday

35.5 30.8 27.3 32.1 23.8 29.9

Find the mean temperature.

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Solution

Daily minimum temperatures = 35.5, 30.8, 27.3, 32.1, 23.8 and 29.9
Thus, we have:

$Mean temperature = \frac{35.5 + 30.8 + 27.3 + 32.1 + 23.8 + 29.9}{6} = \frac{179.4}{6} = 29.9 ° F$

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The daily minimum temperature recorded (in degree F) at a place during a week was as under: Monday Tuesday Wednesday Thursday Friday Saturday 35.5 30.8 27.3 32.1 23.8 29.9 Find the mean temperature.

Daily minimum temperatures = 35.5, 30.8, 27.3, 32.1, 23.8 and 29.9 Thus, we have: Mean temperature=35.5 + 30.8+27.3+32.1+23.8+29.96= 179.46= 29.9°F

The daily minimum temperature recorded (in degree F) at a place during a week was as under:

Monday Tuesday Wednesday Thursday Friday Saturday

35.5 30.8 27.3 32.1 23.8 29.9

Find the mean temperature.

Daily minimum temperatures = 35.5, 30.8, 27.3, 32.1, 23.8 and 29.9
Thus, we have:

$Mean temperature = \frac{35.5 + 30.8 + 27.3 + 32.1 + 23.8 + 29.9}{6} = \frac{179.4}{6} = 29.9 ° F$