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Question

The de Brogile wavelength of the electron in the ground state of the hydrogen atom is (Radius of the first orbit of hydrogen atom = 0.53A
  1. 3.33A
  2. 106A
  3. 1.67A
  4. 0.53A


Solution

The correct option is A 3.33A
2πr=nλ2πr=1×λλ=2πr=2×3.14×0.53=3.33A

 

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