The de Broglie wave length of a riffle bullet of mass 2 grams moving with a velocity of 2 m - sec isA- 6-6 - 10-34-2 - 2 mB- 6-6 - 10-27-2 - 10-3- 2 cmC- 6-6 - 10-34-2 - 10-3- 2 mD- 6-6 - 10-27-2 - 2 m

The correct option is C λ = h/mv 6.625 × 10^ 34/2 × 10^ 3 × 2 ...

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Transverse & Longitudinal Waves

The de Brogli...

Question

The de Broglie wave length of a riffle bullet of mass 2 grams moving with a velocity of 2m/sec is

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27^{\circ} C

m = 1. 67 \times 10^{- 27} kg

k = 1.38 \times 10^{- 23} {J K}^{- 1}

h = 6.6 \times 10^{- 34} Js

α

7.7 \times 10^{- 13} J

6.6 \times 10^{- 24} g

(h = 6.6 \times 10^{- 34} J - s)

Energy of a quanta of frequency $10^{15} H z$ and $h = 6.6 \times 10^{- 34} J - s e c$ will be

2.5 \times 10^{- 10} m

(h = 6.6 \times 10^{- 34} k g m^{2} s^{- 1})

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