Question

The de Broglie wavelength associated with a ball of mass. $200g$ and moving and moving at a speed of $5metres/hour$, is in the order of ($h$ = $6.625\times {10}^{-34}Js$)

• A. 1.342 x 10^-15 m
• B. 1.463 x 10^-20 m
• C. 2.014 x 10^-25 m
• D. 2.385 x 10^-30 m

Answer 1

Answer: (D)

Step 1:

According to de Broglie's equation,

$\lambda =\frac{h}{mv}$

$m=200\times {10}^{-3}kg$

$v=5\times \frac{1}{3600}m/sec$

Step 2:

$\lambda =\frac{6.625\times {10}^{-34}}{2\times {10}^{-1}\times \frac{5}{3600}}$

= $3.6\times 6.625\times {10}^{-31}$

= $2.385\times {10}^{-30}m$

Hence, option (D) is correct.