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Question

The decay constant of 19780Hg (electron capture to 19779Au) is 1.8 ×104   S1. (a) What is the half-life ? (b) What is the average - life ? (c) How much time will it take to convert 25% of this isotope of mercury into gold ?


Solution

Since t12=0.693λ[λDecay Constant]

 t12=0.6931.8×104

=3850sec=64min

(b)   Average life=t120.693

=640.693=92min

(c)0.75=eλτ

ln0.75=λt

t=ln 0.750.00018

=1598.23sec

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