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Question

The decomposition of phosphine (PH3)on tungsten at low pressure is a first-order reaction. It is because the:


A

Rate is proportional to the surface coverage

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B

Rate is inversely proportional to the surface coverage

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C

Rate is independent of the surface coverage

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D

Rate of decomposition is very slow

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Solution

The correct option is A

Rate is proportional to the surface coverage


PH3WP+32H2
This is an example of surface catalyzed unimolecular decomposition.
For the above reaction, rate is given as
Rate=kαp1+αp
Where, p =partial pressure of absorbing substrate.
At low pressure, p << 1 or Rate =kp
So, (p+1) can be neglected.
Thus, the decomposition is predicted to be first order.


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