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Question

The decreasing order of bond angles in hydrides of chalcogens is:
  1. H2O>H2Te>H2Se>H2S
  2. H2S>H2Se>H2S>H2Te
  3. H2O>H2S>H2Se>H2Te
  4. H2Te>H2Se>H2S>H2O


Solution

The correct option is C H2O>H2S>H2Se>H2Te
We know that electronegativity of the central atom decreases down the group. In H2O, the bond pair of electrons is more attracted towards the oxygen atom and as a result there is more bond pair-bond pair repulsion and thus the bond angle increases. So, H2O has the highest bond angle. As size increases down the group, the bond angle decreases.

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