Question

The decreasing order of nucleophilicity of the following is:
I. ${CH}_3{S}^{-}$ II.${CH}_3{O}^{-}$
III.$O{H}^{-}$ IV.$Et{O}^{-}$

• A. IV>III>II>I
• B. I>II>III>IV
• C. IV>III>I>II
• D. II>I>III>IV

Answer 1

The correct option is A IV>III>II>I

Nucleophilicity is measured by relative rate of reaction and how fast an electron pair donor reacts with atom which is bearing leaving group.

$Et{O}^{-}>O{H}^{-}>C{H}_3{O}^{-}>C{H}_3{S}^{-}$

Then,

Option $A$ is correct answer.