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Question

The deflection angle of the pointer of an ideal moving iron ammeter is 20° for 1.0 ampere dc current. If a current of 3 sin (314 t) amperes is passed through the ammeter then the deflection angle is

A
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B
42°
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C
60°
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D
90°
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Solution

The correct option is D 90°
In the moving iron ammeter,

θ i2rms

20θ=(1)2(32)2=29

θ=90

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