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Question

The degree of hydrolysis of ammonium acetate is related to its hydrolysis constant by the expression


  1. a = Kh(1+Kh)

  2. a = Kh(1+Kh2)

  3. a = Kh(1+Kh)

  4. a = Kh(1+Kh)


Solution

The correct option is C

a = Kh(1+Kh)


We have

NH+4 + Ac + H2O = NH4OH + HAc

c(1α)       c(1α)                     cα         cα

Kh = [NH4OH][HAc][NH+4][AC] = (cα)(cα)(c(1α))(c(1α)) = α2(1α)2

or α1α = Kh or α = Kh1+Kh

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