The degree of the equation k -1 x 2-3-2 x -7- where k -1 is-A- 1B- 2C- 3D- 4

The correct option is A 1Given that, x^2(k+1)+3/2x=7 Given, k = 1 ⇒ x^2( 1+1)+3/2x=7 ⇒ 3x 14=0 which is not a quadratic equation. ...

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Degree of a Polynomial

The degree of...

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The degree of the equation $(k + 1) x^{2} + \frac{3}{2} x = 7$ , where k = -1 is .

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What is the degree of following equation?

$(k + 1) x^{2} + \frac{3}{2} x = 7$ , where k = -1

The degree of the equation $(k + 1) x^{2} + \frac{3}{2} x = 7$ , where k = -1 is .

7 x^{2} - 6 x y z - 3 = 9 x

x + k y = 4

\frac{d^{2} y}{d x^{2}} = \sqrt[3]{1 + (\frac{d y}{d x})^{4}}

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