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Question

The density of a mixture of CO and CO2 at 303 K and 73 cm Hg is 1.5 g L1. What is the mole percent of CO and CO2 respectively in the mixture?

A
32.19%, 67.81%
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B
31.19%, 67.81%
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C
41.2%, 58.8%
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D
40.2%, 58.8%
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Solution

The correct option is A 32.19%, 67.81%
Let M be the average molecular mass of the mixture.
PV=wRTM
or, P=wRTM×V
or, P=dRTM

P=7376 atm, d=1.5 g L1, M=?
T=303 K, R=0.0821 L atm K1 mol1

7376=1.5×0.0821×303M
M=38.85 g/mol

Suppose, the total moles = 100
Moles of CO=a
Moles 0f CO2=100a
Mass of CO=28a
Mass of CO2=(100a)44
Total mass =28a+(100a)44
Molar mass of the mixture=28a+(100a)44100
38.85=28a+(100a)44100
a=32.19
Mole percent of CO=32.19%
Mole percent of CO2=(10032.19)%=67.81%

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