    Question

# The density of a mixture of CO and CO2 at 303 K and 73 cm Hg is 1.5 g L−1. What is the mole percent of CO and CO2 respectively in the mixture?

A
32.19%, 67.81%
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B
31.19%, 67.81%
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C
41.2%, 58.8%
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D
40.2%, 58.8%
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Solution

## The correct option is A 32.19%, 67.81%Let M be the average molecular mass of the mixture. PV=wRTM or, P=wRTM×V or, P=dRTM P=7376 atm, d=1.5 g L−1, M=? T=303 K, R=0.0821 L atm K−1 mol−1 ∴7376=1.5×0.0821×303M M=38.85 g/mol Suppose, the total moles = 100 Moles of CO=a Moles 0f CO2=100−a Mass of CO=28a Mass of CO2=(100−a)44 Total mass =28a+(100−a)44 Molar mass of the mixture=28a+(100−a)44100 38.85=28a+(100−a)44100 a=32.19 Mole percent of CO=32.19% Mole percent of CO2=(100−32.19)%=67.81%  Suggest Corrections  0      Similar questions  Explore more